49d^2-36d+0=0

Solution for 49d^2-36d+0=0 equation:

49d^2-36d+0=0

We add all the numbers together, and all the variables

49d^2-36d=0

a = 49; b = -36; c = 0;
Δ = b2-4ac
Δ = -362-4·49·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-36}{2*49}=\frac{0}{98}
=0
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+36}{2*49}=\frac{72}{98}
=36/49
$